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 <title><![CDATA[不信您就试试看]]></title>
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 <description><![CDATA[Latest 20 replies of 不信您就试试看]]></description>
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 <description><![CDATA[信, 当然信.]]></description>
 <link><![CDATA[http://bachinese.com/forum/job.php?action=topost&tid=7550&pid=41531]]></link>
 <author><![CDATA[阿平]]></author>
 <category><![CDATA[乱讲]]></category>
 <pubdate><![CDATA[Sat, 27 Aug 2005 23:22:14 +0000]]></pubdate>
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 <description><![CDATA[下面是引用小平于2005-08-24 23:15发表的:
当然啦，这个就相当于。
你家的号码：xyzabcd

TA让你输入xyz, 然后用xyzX10000再加上你自己输入的abcd，
当然结果就是xyzX10000+abcd=xyzabcd

Hey, you are ahead of me.]]></description>
 <link><![CDATA[http://bachinese.com/forum/job.php?action=topost&tid=7550&pid=41466]]></link>
 <author><![CDATA[ok5]]></author>
 <category><![CDATA[乱讲]]></category>
 <pubdate><![CDATA[Thu, 25 Aug 2005 12:34:05 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[当然啦，这个就相当于。
你家的号码：xyzabcd

TA让你输入xyz, 然后用xyzX10000再加上你自己输入的abcd，
当然结果就是xyzX10000+abcd=xyzabcd]]></description>
 <link><![CDATA[http://bachinese.com/forum/job.php?action=topost&tid=7550&pid=41443]]></link>
 <author><![CDATA[小平]]></author>
 <category><![CDATA[乱讲]]></category>
 <pubdate><![CDATA[Thu, 25 Aug 2005 06:15:08 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[x:任意数值， y:任意4位数
((X*80+1)*250+y+y-250)/2
=(20000*x+250+2y-250)/2
=(x*20000+2y)/2
=x*10000+y

谁敢不信？
如果从来不用后4位数y，最后能通过对前3-4位数x的计算得到后四位y, 那I可就真服了him/her，可是，这有可能吗？]]></description>
 <link><![CDATA[http://bachinese.com/forum/job.php?action=topost&tid=7550&pid=41441]]></link>
 <author><![CDATA[伍胥之]]></author>
 <category><![CDATA[乱讲]]></category>
 <pubdate><![CDATA[Thu, 25 Aug 2005 02:36:15 +0000]]></pubdate>
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